How cold is it outside? The temperature alone is not enough to provide the answer. Other factors including wind speed, relative humidity, and sunshine play important roles in determining coldness outside. In 2001, the National Weather Service (NWS) implemented the new wind-chill temperature to measure the coldness using temperature and wind speed.
not enough to provide the answer. Other factors including wind speed, relative humidity, and sunshine play important roles in determining coldness outside. In 2001, the National Weather Service (NWS) implemented the new wind-chill temperature to measure the coldness using temperature and wind speed. The formula is:
twc = 35.74 + 0.6215ta - 35.75v0.16 + 0.4275tav0.16
where ta is the outside temperature measured in degrees Fahrenheit and v is the speed measured in miles per hour. twc is the wind-chill temperature. The formula cannot be used for wind speeds below 2 mph or temperatures below –58°F or above 41°F.
Write a program that prompts the user to enter a temperature between –58°F and
41°F and a wind speed greater than or equal to 2 and displays the wind-chill temperature. Use pow(a, b) to compute v0.16
#Beginner
In gcc c++ compiler using namespace std;
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
float ta,v;
cout<<"Enter the temperature in Fahrenheit :";
cin>>ta;
cout<<"Enter the wind speed in miles per hour :";
cin>>v;
float twc;
twc=35.74+0.6215*ta-35.75*pow(v,0.16)+0.4275*ta*pow(v,0.16);
cout<<"The wind chill index is :"<<twc;
return 0;
}
Output
Enter the temperature in Fahrenheit :134
Enter the wind speed in miles per hour :5
The wind chill index is :146.881
[Program finished]
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